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4n^2-37n-30=0
a = 4; b = -37; c = -30;
Δ = b2-4ac
Δ = -372-4·4·(-30)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-43}{2*4}=\frac{-6}{8} =-3/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+43}{2*4}=\frac{80}{8} =10 $
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